Gérer les informations de debug en JavaScript

                                            
                                                <script language="javascript">
                                                
                                                    var debugMode = false;
                                                
                                                    function consoleLog(pMsg) {
                                                        if (window.console && window.console.log && debugMode == true) {	
                                                            console.log(pMsg);
                                                        }
                                                    }
                                                    
                                                </script>
                                            
                                        

                                            
                                                <script language="javascript">
                                                    
                                                    debugMode = true;
                                                    
                                                    if (x > y) {
                                                        consoleLog("X est superieur a Y");
                                                    } else {
                                                        consoleLog("Y est superieur ou egal a X");
                                                    }
                                                    
                                                </script>